## TAYLOR TABLE MODELLING FOR FOURTH-ORDER-APPROXIMATION OF SECOND ORDER DERIVATIVE

DESCRIPTION:

Using the central and skewed scheme methods initially, we have to develop the Taylor table, which should be converted into a matrix and solved for the constants. These constants help in solving the second order differential equation. Finally, the error results are plotted and studied.

1. CENTRAL DIFFERENCING SCHEME:

In central differencing method, we will be solving with this format of stenciling the points.

(∂^2 f)/(∂x^2) = a.f(i-2)+b.f(i-1)+c.f(i)+d.f(i+1) +e.f(i+2) This table can be converted into the matrix form as: After solving the matrix for constants a, b, c, d, e we should substitute the values in the table for the fifth term of the taylor series and check for the value of the sum of the fifth terms.

By checking we get,

a = -0.0833

b = 1.33

c = -2.5

d = 1.33

e = -0.0833

and hence  ((-32*a)-(b)+(d)+(32e))/120 become zero.

Similar steps have to be followed for the skewed scheme also.

2. LEFT-SIDE SKEWED SCHEME: CONSTANTS:

a = 3.75

b = -12.833

c = 17.833

d = -13.0

e = 5.0833

g = -0.833

3. RIGHT-SIDE SKEWED SCHEME: CONSTANTS:

a = 3.75

b = -12.833

c = 17.833

d = -13.0

e = 5.0833

g = -0.833

MAIN CODE:

clear all
close all
clc

% Taylor table

x = pi/3;
dx = linspace(pi/4,pi/400,50);

% analytical function = exp(x)*cos(x)
% f'(x) = exp(x)*cos(x) - exp(x)*sin(x)
% f''(x) = -2*exp(x)*sin(x)

%1. central diff
%2. skew right scheme
%3. skew left scheme

for n = 1: length(dx)
error1(n) = taylorfunc(x,dx(n),1);
error2(n) = taylorfunc(x,dx(n),2);
error3(n) = taylorfunc(x,dx(n),3);
error4(n) = taylorfunc(x,dx(n),4);
error5(n) = taylorfunc(x,dx(n),5);
end

figure(1)
loglog(dx,error1,'linewidth',2)
hold on
loglog(dx,error2,'linewidth',2)
loglog(dx,error3,'linewidth',2)
legend('4th order central appx','4th order left skewed appx','4th order right skewed appx','Location','southeast')
xlabel('x_value')
ylabel('error')
title('COMPARISION OF CENTRAL AND SKEWED SCHEME ERRORS')

figure(2)
loglog(dx,error1,'linewidth',1)
hold on
loglog(dx,error2,'linewidth',1)
loglog(dx,error3,'linewidth',1)
loglog(dx,error4,'linewidth',1,'LineStyle','- -')
loglog(dx,error5,'linewidth',1,'LineStyle','- .')
legend('4th order central appx','4th order left skewed appx','4th order right skewed appx','1st order forward appx','1st order backward appx','Location','southeast')
xlabel('x_value')
ylabel('error')
title('CENTRAL,FORWARD,BACKWARD AND SKEWED SCHEME ERRORS')


FUNCTION CODE-1:

function error = taylorfunc(x,dx,i)

if i == 1

%central diff scheme
%calculating constants: a, b, c, d, e

A = [1 1 1 1 1; -2 -1 0 1 2; 2 1/2 0 1/2 2; -8/6 -1/6 0 1/6 8/6; 16/24 1/24 0 1/24 16/24];
B = [0; 0; 1; 0; 0];
X = A^-1*B;

% Extracting constants
a = X(1);
b = X(2);
c = X(3);
d = X(4);
e = X(5);

central_diff = ((a*f(x-(2*dx)))+(b*f(x-dx))+(c*f(x))+(d*f(x+dx))+(e*f(x+2.*dx)))/(dx^2);
error = abs(central_diff - f2(x));

end

if i == 2

%left skewed scheme
%calculating constants: a, b, c, d, e
A = [1 1 1 1 1 1; 0 -1 -2 -3 -4 -5; 0 1/2 2 9/2 16/2 25/2; 0 -1/6 -8/6 -27/6 -64/6 -125/6; 0 1/24 16/24 81/24 256/24 625/24; 0 -1/120 -32/120 -243/120 -1024/120 -3125/120];
B = [0; 0; 1; 0; 0; 0];
X = A^-1*B;

% Extracting constants
a = X(1);
b = X(2);
c = X(3);
d = X(4);
e = X(5);
g = X(6);

skewleft_diff = ((a*f(x))+(b*f(x-dx))+(c*f(x-2*dx))+(d*f(x-3*dx))+(e*f(x-4*dx))+(g*f(x-5*dx)))/(dx^2);

error = abs(skewleft_diff - f2(x));

end

if i == 3

%right skewed scheme
%calculating constants: a, b, c, d, e
A = [1 1 1 1 1 1; 0 1 2 3 4 5; 0 1/2 2 9/2 16/2 25/2; 0 1/6 8/6 27/6 64/6 125/6; 0 1/24 16/24 81/24 256/24 625/24; 0 1/120 32/120 243/120 1024/120 3125/120];
B = [0; 0; 1; 0; 0; 0];
X = A^-1*B;

% Extracting constants
a = X(1);
b = X(2);
c = X(3);
d = X(4);
e = X(5);
g = X(6);

skewright_diff = ((a*f(x))+(b*f(x+dx))+(c*f(x+(2*dx)))+(d*f(x+(3*dx)))+(e*f(x+(4*dx)))+(g*f(x+5*dx)))/(dx^2);
error = abs(skewright_diff - f2(x));

end

if i == 4
%forward differencing
fd_diff = (f(x+2*dx)-(2*f(x+dx))+f(x))/(2*(dx^2));
error = abs(fd_diff - f2(x));
end

if i == 5
%forward differencing
back_diff = [f(x)-(2*f(x-dx))+f(x-2*dx)]/(2*(dx^2));
error = abs(back_diff - f2(x));
end

end

FUNCTION CODE-2:

function [f_act] = f(x)

f_act = (exp(x)*cos(x));

end

FUNCTION CODE-3:

function out = f2(x)
out = -2*exp(x)*sin(x);
end

RESULT:

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